The molar mass of =Ba(OH)2=Ba(OH)_2=Ba(OH)2
Molarity=Molarity=Molarity= MolesLiterMoles\over LiterLiterMoles
=171.33g/mol= 171.33g/ mol=171.33g/mol
We need to turn 35ml35 ml35ml of 0.200molesBa(OH)20.200moles Ba(OH)_20.200molesBa(OH)2 into its equivalent mass
This is done by multiplying;
0.200×171.3435ml0.200\times 171.34\over35ml35ml0.200×171.34 =0.979gBaOH= 0.979g BaOH=0.979gBaOH
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