Answer to Question #136130 in General Chemistry for Javier

Question #136130
If you have 15.0 g Na, how many grams of O2 are required for reaction?
1
Expert's answer
2020-10-02T14:23:26-0400

STEP I : BALANCED EQUATION AND MOLES OF Na

2Na(s) + O2(g) \to 2Na2O(s)


Moles of Na in 15.0g =massRAM=15.0g23g/mol= \dfrac{mass}{RAM} = \dfrac{15.0g}{23g/mol}


=0.652moles=0.652moles


STEP II : MOLES AND MASS OF O2


From the equation, mole ratio of Na:O2 = 1:1


Moles of oxygen =12x0.652mol=0.326moles=\dfrac{1}{2}x0.652mol = 0.326moles


Mass of oxygen = Moles x Molar Mass

= 0.326mol x 16g/mol

= 5.22g


Mass of oxygen


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