Question

How many grams of O2 are needed to react with 8.10 moles NH3

Answer 1

Solution:

Oxidation reaction with the formation of nitrogen and water:

4NH₃ + 3O₂ = 2N₂ + 6H₂O

Molar mass of O₂ 32 gram/mol.

According to the reaction equation, for 4 moles of ammonia NH₃ are needed 3 moles of oxygen O₂.

And then, for 8.10 moles of NH₃ are needs mass of O₂:

 $(8.10mol NH3×3mol O2) / 4mol NH3 × 32gram/mol O2$ = 194.4 gram O₂

Answer: for 8.10 moles NH₃ are needed to react 194.4 grams O₂.