Answer to Question #136098 in General Chemistry for Emer Lindsay
2020-09-30T17:25:36-04:00
A 2.724 grams sample of diethyl ether was analyzed using combustion analysis. Produced by the combustion were 6.470 g of CO2 and 3.311 g of water. What is the empirical formula of diethyl ether?
1
2020-10-01T07:52:24-0400
"n(CO_2) = {m \\over M} = {6.470g \\over 44.01g\/mol} = 0.147mol"
"n(H_2O) = {3.311g \\over 18.01528g\/mol} = 0.184mol"
"n(C) = n(CO_2) = 0.147mol"
"n(H) = 2n(H_2O) = 2*0.184mol = 0.368mol"
"{n(C) \\over n(H)} = {0.147 \\over 0.368} = {1 \\over 2.5} = {2 \\over 5}"
"C_2H_5O = C_4H_{10}O" ANSWER: C 4 H 10 O
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