formula of sodium carbonate is Na2CO3 and molar mass of it = (23*2)+(12*1)+(16*3) = 46+12+48 = 106 g\mol (here '*' corresponds to multiplication)
so mol of sodium carbonate = (mass of carbonate \ molar mass)
=(25\106) = 0.236 mol
now in one molecule of sodium carbonate contains 2 Na , 1 carbon and 3 oxygen atom , so total no of atom in one molecule is (2+1+3) = 6 no of atoms
we know from mole concept that 1 mol sodium carbonate contains avogadro no of sodium carbonate molecule that is = 6.023 * 1023 no of molecules = 6*6.023*1023 no of atoms.
so the no of atoms in 0.236 mol of sodium carbonate = 0.23*6*6.023*1023
= 8.311*1023 no of atoms. (ans)
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