Answer to Question #135959 in General Chemistry for C

Question #135959

How many grams of nitrogen gas are in a 2 L container at 1.5 atm and 25 centigrade?


1
Expert's answer
2020-10-01T07:55:30-0400

Use Ideal Gas Law

PV=nRTPV=nRT

n=PVRT=1.5atm×2L0.082L×atmmol×K×(273+25)=0.123molesn=\frac{PV}{RT}=\frac{1.5 atm\times 2L}{0.082 \frac{L\times atm}{mol\times K}\times (273+25)}=0.123 moles


convert moles to grams

0.123moles(N2)×28.01g(N2)1mole(N2)=3.4g(N2)0.123 moles (N_2)\times \frac{28.01 g (N_2)}{1 mole (N_2)}=3.4 g (N_2)


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