How many grams of nitrogen gas are in a 2 L container at 1.5 atm and 25 centigrade?
Use Ideal Gas Law
"PV=nRT"
"n=\\frac{PV}{RT}=\\frac{1.5 atm\\times 2L}{0.082 \\frac{L\\times atm}{mol\\times K}\\times (273+25)}=0.123 moles"
convert moles to grams
"0.123 moles (N_2)\\times \\frac{28.01 g (N_2)}{1 mole (N_2)}=3.4 g (N_2)"
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