How many grams of nitrogen gas are in a 2 L container at 1.5 atm and 25 centigrade?
Use Ideal Gas Law
PV=nRTPV=nRTPV=nRT
n=PVRT=1.5atm×2L0.082L×atmmol×K×(273+25)=0.123molesn=\frac{PV}{RT}=\frac{1.5 atm\times 2L}{0.082 \frac{L\times atm}{mol\times K}\times (273+25)}=0.123 molesn=RTPV=0.082mol×KL×atm×(273+25)1.5atm×2L=0.123moles
convert moles to grams
0.123moles(N2)×28.01g(N2)1mole(N2)=3.4g(N2)0.123 moles (N_2)\times \frac{28.01 g (N_2)}{1 mole (N_2)}=3.4 g (N_2)0.123moles(N2)×1mole(N2)28.01g(N2)=3.4g(N2)
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