Question #135962
a reaction of 12.640g of copper oxide with 0.316g hydrogen produces 2.844g of water and x g of copper. x = ____ g
Answer
CuO (s) +H2(g) –> Cu(s)+H2O(g)
Mol of CuO= 12.64/80=.0158
Mol of H2 = 0.316/2=0.158
Mol of H2O = 2.844/18= 0.158
Mol ratio of CuO: H2: Cu: H2O is 1:1:1:1
Mol of Cu = 1×0.158=0.158
Mass of Cu formed, X = 0.158×64
= 10.112g
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