The SS Hindenburg
contained about 5.33 × 105 g of H2 gas when it burned at Lakehurst, New Jersey, in 1937. The chemical reaction is as follows:
2H2 + O2→ 2H2O
How many grams of H2O were produced?
M(H2) = 2 g/mol
M(H2O) = 18 g/mol
n=m/M
n(H2)="\\frac{5.33\\times10^5}{2}" = 2.665×105 mol
Proportion from the reaction:
n(H2) = n(H2O) = 2.665×105 mol
m(H2O)= 18×2.665×105 = 47.97×105 g
Answer: 47.97×105 g
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