pH=pKa+log[salt][acid]pH=4.756+log20×0.110×0.1=4.756+log2=5.056pH=pK_a+\log\frac{[salt]}{[acid]}\\pH=4.756+\log\frac{20\times0.1}{10\times0.1}=4.756+\log2=5.056pH=pKa+log[acid][salt]pH=4.756+log10×0.120×0.1=4.756+log2=5.056
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