Question

A gas, initially at 292K, enclosed in a bulb of volume 15.1mL at a pressure of 90.2kPa, was first expanded into a reaction vessel so that the total volume was 182.2mL and then heated to 428K. What is the final pressure in the vessel?

Answer 1

Solution.

$p1 \times V1 = p2\times V2$

$p2 = \frac{p1 \times V1}{V2}$

p2 = 7475.41 Pa

$\frac{p2}{T1} = \frac{p3}{T2}$

$p3 = \frac{p2 \times T2}{T1}$

p3 = 10957.11 Pa

Answer:

p3 = 10957.11 Pa