Answer to Question #133158 in General Chemistry for mike

Question

A sample of argon gas that originally occupied 14.6L at 25.0oC was heated to 50.0oC at constant pressure. What is its new volume?

Answer 1

Charles law formula is

$\dfrac{V1}{T1}=\dfrac{V2}{T2}$ Where,

V1=14.6L

V2=??

Converting temperature into kelvin

T1=25+273=298K

T2=50+273=323k

Substituting values into the formula

$\dfrac{14.6}{298}=\dfrac{v2}{323}$

Making V2 the subject

$V2=\dfrac{14.6*323}{298}$

$V2=15.8L$

The new volume is $15.8L$