Question

A sheet of gold weighing 10.0 g and at a temperature of 18.0°C is placed flat on a sheet of iron weighing 20.0 g and at a temperature of 55.6°C. What is the final temperature of the combined metals? Assume that no heat is lost to the surroundings. (Hint: The heat gained by the gold must be equal to the heat lost by the iron. The specific heats of the gold and iron are 0.129 and 0.444 J/(g∙℃), respectively.

Answer 1

Two q's to 0.

(10.0 Au)(0.129)(Tf-18.0°C) + (20.0g Fe)(0.444)(Tf-55.6°C)=0

(1.29Tf-23.22) + (8.88Tf-502.608) = 0

10.17Tf = 525.828

Temperature final = 51.70°C