A sample of nitrogen gas expands in volume from 1.6 L to 5.4 L at constant temperature
a) Work done by vaccumn = zero .
b) Work done = p ( v2 - v1 ) = 0.80 ( 5.4 - 1.6 ) atm . liter = 3.04 atm . = ( 3.04 * 101.2 ) j =
307.6 j
c) Work done = p ( v2 - v1 ) .
= 3.7 ( 5.4 - 1.6 ) atm . liter
= 14.06 atm . liter
= 14.06 * 101.2 j .
= 1422.872 j .
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