Answer to Question #130633 in General Chemistry for Shikwambi

Question

a) What does the 60% ethane conversion mean? What will the concentration of ethane in the outlet of the cracker be in mass%?

b) What does the 80% ethylene yield mean? What will the concentration of ethylene in the outlet of the cracker be in mass%?

Answer 1

a) this means that 60% of ethane has reacted from its the original amount

C(ethane)= Mo(ethane) *0.4/M(mix)*100%

where C(ethane) - mass concentration of ethane, Mo(ethane)- origin mass of ethane, M(mix)- mass of mixture in the outlet of the cracker

If ethane and ethylene are the only reagents then C(ethane) = 40 mass%

b) this means that 80% of the theoretical possible amount of ethylene was obtained

C(ethylene)= M(ethylene)/M(mix)*100%

where C(ethylene) - mass concentration of ethylene, M(ethylene)- mass of ethylene, M(mix)- mass of mixture in the outlet of the cracker

If ethane and ethylene are the only reagents then C(ethylene) = 80 mass%