The equation for the reaction is;
"Fe(C_2H_3O_2)_2+KI\\to K(C_2H_3O_2)_2+FeI_2"
"K," a group "1" element dissociates completely hence "KCH_3CO_2" becomes "K^+" and "CH_3CO_2^-"
"Fe^{2+}" and "I^-" do not dissociate in water hence Iron (II) iodide"(FeI_2)" is the precipitate.
The correct answer is "B(FeI_2)"
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