Answer to Question #129952 in General Chemistry for Mary

Question

Hi,
A neutralization of a strong acid by a strong base gave out 4590 J of heat energy.

Determine the enthalpy change (in kJ) for the reaction.

Please Give your answer to three significant figures.Thanks

Answer 1

Heat released $=$ Enthalpy change $= 4590\ J$ $=\frac{4590}{1000}KJ= 4.590 \ KJ$

Enthalpy change in three significant figures will be $4.59 \ KJ$