Question #129941

Good day,

When a solution of KOH is neutralized by hydrochloric acid, the solution gets hot.

Calculate the change in heat of the solution (in J).


Mass of combined solution = 42.0 g

Temperature change of the solution = 13.4 K

Specific heat capacity of the solution = 4.18 J/g·K


Please Give your answer to three significant figures.


Thanks


1
Expert's answer
2020-08-21T04:11:09-0400

Mass of solution (m)=42.0 g(m)= 42.0\ g

Temperature change (T)=13.4 K(\triangle T)=13.4\ K

Specific heat capacity(C)=4.18J/g.K(C)=4.18J/g.K

Heat change will be mCT=42.0×4.18×13.4=2352.504 JmC\triangle T=42.0\times 4.18\times 13.4=2352.504\ J

=2.35×103J=2.35\times 10^3 J (in 3 significant figures)


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