The balanced equation isLiOH +HNO3 →LiNO3 +H2O
In a neutralization reaction when a base or an acid isadded to an aqueous solution ofan acid or a baserespectively the solution temperature increases.
The\ following\ formula \ is\ used\ to\ calculated\ produced \newline heat\
q=mcsΔT where,ΔT is the temperature change =16.6Km =mass of substance in grams =??cs=specific heat =4.18J/gKq=heat produced =4530J
Substituting values to the equation we get,
4530=m ∗ 4.18 ∗16.64530=69.388 mm=69.3884530
m=65.2g\
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