Question

Good day,

A fuel was used to heat water in a calorimetry experiment. Propane was burnt causing a temperature change of 2.75 K in 700 g of water (specific heat capacity = 4.18 J/g·K).

Calculate the heat change of the water.

Heat change (J) = mass (g) × specific heat capacity (J/g·K) × temperature change (K)

Give your answer to three significant figures.    Thanks

Answer 1

As per the question

$\triangle T=2.75 K$

Specific heat $(C)=4.18 J/g.K$

Mass of water $(m)= 2.75\ g$

Heat change in water$= mC\triangle T= 2.75\times 4.18\times 700=8046.5 J$

$=8.05\times 10^3J$ (in 3 significant figures)