Answer to Question #127555 in General Chemistry for mike

Question

The following solutions are mixed:
20cm3 of 0.2M NaCl, 40cm3 of 0.1M MgCl2 and 40cm3 of 0.2M AlCl3
After thorough mixing an accident occurs. (Guess who?) Half the mixture is lost.
Calculate the concentration of the chloride ion remaining in the solution.

Answer 1

Milli Moles of Cl^- in NaCl = 4 Millimole ..

Milli Moles of Cl- in MgCl₂ = 8 Millimole ..

Milli Moles of Cl- in AlCl₃ = 24 Millimole ..

Total Milli Moles of Cl- = 18 Millimole .

Total Volume Of Solution In ml = 100 ml .

Half Solution Lost So , Half Moles And Half Volume Lost .

Concentration of Cl^- = MilliMoles Of Cl^- / Volume Of SOlution in ml .

= 18 / 50 M .

= 0.36 M . ANSWER .