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Answer to Question #127551 in General Chemistry for mike
Question #127551
An experiment requires 0.059mol of calcium carbonate, CaCO3. What mass of calcium carbonate needs to be weighed out?
Expert's answer
Answer:M"(CaCO_{3})" = "100( \\tfrac{g}{mol})"
Therefore mass of calcium corbanate = amount of calcium corbanate x molar mass
m = 0.059 x 100 = 5.9 g
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