Answer to Question #127551 in General Chemistry for mike

Question #127551
An experiment requires 0.059mol of calcium carbonate, CaCO3. What mass of calcium carbonate needs to be weighed out?
1
Expert's answer
2020-07-27T05:35:45-0400

Answer:M"(CaCO_{3})" = "100( \\tfrac{g}{mol})"

Therefore mass of calcium corbanate = amount of calcium corbanate x molar mass


m = 0.059 x 100 = 5.9 g

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