Answer to Question #127554 in General Chemistry for mike

Question

In order to prepare a standard solution of 0.100M sodium carbonate, (MM:106g mol-1), 10.6g of Na2CO3 should be dissolved in:
A. 1000cm3 of water
B. enough water to make 1000cm3 of solution
C. 1000g of water
D. enough water to make 1000g of solution

Answer 1

molarity=mol/l

m(Na₂CO₃)=10.6g

MM(Na₂CO₃)=106g*mol^-1

n=m/M=10.6/106=0.1mol

l=n/molarity=0.1/0.1=1l=1000cm³

Answer: A. 1000 сm³ of water