Answer to Question #126694 in General Chemistry for Philip

Question

120cm3 of hydrogen gas is sparked with 40cm3 of oxygen gas in a eudiometer tube at 150 degree centigreed and 1atm
(a) which of the gas is in excess and by how much in volume
(b) find the volume of the residual gas
(c) what is the percentage of steam in the residual gases

Please show all workings

Answer 1

Given volume of H₂ (g) = 120 cm³ = 120 ml .

Given Volume Of O₂ (g) = 40 cm³ = 40 ml .

2 H₂ (g) + O₂ ( g) ----------> 2 H₂O (g)) .

2 ml of H₂ ( g) React With 1 ml Of O₂ ( g) .

So , 40 ml Of O₂ ( g) React With 80 ml ( g) of H₂ ( g) .....

(a) O₂ (g) is limiting So , Totally Consumed and H₂( g) present in Excess .

Volume of H₂ ( g) which is present in Excess = ( 120 - 80 ) ml .= 40 ml .Answer .............................

( b)  volume of the residual gas ( H₂O (g) + H₂(g) ) . = 80 ml . + 40 ml = 120 ml . Answer .....

( c)

percentage of steam in the residual gases

= volume of steam * 100 / total volume of residual gas ::::::::

= 80 ml * 100 / 120 ml = 66.66 % .......... Answer .