25.00cm of 0.100M NaOH is needed to titrate 25.00cm of a solution of hydrochloric acid. Calculate the
concentration of the acid.
NaOH + HCl → NaCl + H2O
The mole ratio NaOH:HCl is 1:1
Amount of sodium hydroxide = 0.100 (mol/L) × 0.025 L = 0.0025 mol
Therefore 0.0025 mol of NaOH reacts with 0.0025 mol of HCl
Concentration of hydrochloric acid = 0.0025 mol / 0.025 L = 0.100 M
Answer: 0.100 M
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