Solution.
w(xCr)=1-w(52Cr)-w(53Cr)-w(54Cr)=1-0.828-0.109-0.027=0.036 (3.6 %)
Ar(Cr)=Ar(52Cr)*w(52Cr)+Ar(53Cr)*w(53Cr)+Ar(54Cr)*w(54Cr)+Ar(xCr)*w(xCr)
52.09=52*0.828+53*0.109+54*0.027+Ar(xCr)*0.036
Ar(xCr)=50
Answer: the mass number of this isotope is 50.
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