Question #123373
If a 320. mg sample of technetium−99m is used for a diagnostic procedure, how much Tc−99m remains after each interval: (a) 6.0 h; (b) 2 days? (assume that a day is an exact value) The half-life of technetium−99m is 6.0 hours.
Expert's answer
Explanation:
The basic formula for half life equations is
A=P(1/2)t/h
A= amount remaining
P= original amount
t= elapsed time
h=half life time
a) P=320, t=6,h=6
A=320(1/2)6/6
=160mg
b) P=320, t=48hrs, h=6hrs
A=320(1/2)48/6
=1.25mg
