Answer to Question #123312 in General Chemistry for Izzy

Question

For Solutions and Solubility

200.0 mL of a 0.500 mol/L solution of sodium hydroxide is added to 300.0 mL
of a 0.300 mol/L solution of phosphoric acid.

What is the pH of the final solution created?

Answer 1

SOLUTION:-

200ML of 0.500mol/L NaOH

300ML Of 0.300mol/L H₃ PO₄

3 NaOH_(aq) + H₃PO_{4 (aq)} - NaPO_4(aq) + 3 H₂O_(l)

Mole ratio 3 :1:1:3

Therefore :-

[(3)(0.500)] : [(1)(0.300)] = 1:3

= PH 1.5