Answer to Question #122326 in General Chemistry for Leslie

Question

A neutron is a spherical object that has a mass of 0.000000000000000000000000001675 kilograms and a radius of 0.8 femtometers. The volume of a sphere is (4/3)(π)r3. What is the density of a proton?

Answer 1

Density of a proton is defined as'

$Density (\rho)=\dfrac{Mass(M)}{Volume(V)}$ and'

$Volume(V)=(\dfrac{4}{3})\pi r^{3}$

We are given radius (r) =0.8fm

Converting into metres.

$1fm=1.0*10^{-15}m$

$0.8fm=??$

$=8*10^{-16}m$

Therefore,

$V=1.33*3.14*(8*10^{-16})^{3}$

$=2.138*10^{-45}m^3$

So,

$\rho=\dfrac{1.675*10^{27}}{2.138*10^{-45}}$

$=7.834*10^{71}kg/m^3$