Answer to Question #122229 in General Chemistry for Kadin Johnson

Question

Calculate Kb for the conjugate base of carbonic acid, H₂CO₃(aq), Ka = 4.4x10⁻⁷

Answer 1

The value of base ionisation constant $Kb$ is calculated using the following formula,

$Kb=\dfrac{Kw}{Ka} where,$

$Ka$ is the acid dissociation constant

$Kw$ is water dissociation constant

We are given,

$Ka=$ $4.4*10^{-7}$

$Kw=1.0*10^{-14}$

Substituting

$Kb=\dfrac{1.0*10^{-14}}{4.4*10^{-7}}$

$=2.3*10^{-8}$

$Kb$ for conjugate base of carbonic acid$=2.3*10^{-8}$