Question #122278
What is the enthalpy of formation of tetrachloroethane from ethene and chlorine
1
Expert's answer
2020-06-18T14:45:49-0400

Enthalpy of formation=ΔHf=\Delta Hf


The equation for the reaction is

C2H4(g) +2Cl2(g)\to C2H2Cl4(l)


ΔHf0={mΔHf[products]}{nΔHf[reactants]}\Delta Hf^0=\lbrace m\Delta Hf \lbrack products\rbrack\rbrace-\lbrace n\Delta Hf\lbrack reactants \rbrack\rbrace

ΔHf\Delta Hf of C2H4 =52.4kJ/mol=52.4kJ/mol

ΔHf\Delta Hf of Cl2=0kJ/mol=0kJ/mol

According to Gundry and Head , 1978, ΔHf\Delta Hf of tetrachloroethane is 193.5kJ/mol-193.5kJ/mol

therefore,

ΔHf0={193.5kJ/mol}{[52.4+(20)]kJ/mol}\Delta Hf^0=\lbrace-193.5kJ/mol\rbrace-\lbrace\lbrack52.4+(2*0)\rbrack kJ/mol\rbrace

ΔHf0=245.9kJ/mol\Delta Hf^0=-245.9kJ/mol






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