Enthalpy of formation=ΔHf
The equation for the reaction is
C2H4(g) +2Cl2(g)→ C2H2Cl4(l)
ΔHf0={mΔHf[products]}−{nΔHf[reactants]}
ΔHf of C2H4 =52.4kJ/mol
ΔHf of Cl2=0kJ/mol
According to Gundry and Head , 1978, ΔHf of tetrachloroethane is −193.5kJ/mol
therefore,
ΔHf0={−193.5kJ/mol}−{[52.4+(2∗0)]kJ/mol}
ΔHf0=−245.9kJ/mol
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