Question

In a synthesis reaction, what is the mass of magnesium metal required to react with 43.6 L of bromine gas at STP?

Answer 1

Reaction is -

$$Mg\ +\ Br_2\to MgBr_2$$

1mole Mg reacts with 1 mole of bromine

Moles of bromine $=\frac{43.6}{22.4}= 1.9464\ mole$

Moles of Mg = 1.9464

Mass of Mg =$1.9464\times 24=46.71\ gm$