Solution.
V1=100mL=0.1L;
c1=0.500mol/L;
c2=0.250mol/L;
V2−?;
c1V1=c2V2,
c1,V1 - the molarity and volume of the concentrated solution;
c2,V2 - the molarity and volume of the diluted solution;
V2=c2c1V1;
V2=0.250mol/L0.500mol/L⋅0.1L=0.2L;
It is impossible to prepare such a solution, because it is necessary to take twice as much acid as the volume of the whole solution should be, because pure acid has twice less concentration than dilute.
Answer: It is not possible to prepare the solution.
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