Answer to Question #118849 in General Chemistry for ava holmberg

General Chemistry

Question #118849

a 0.750 m solution of ascorbic acid has a pH of 2.11. calculate the ka of ascorbic acid

Expert's answer

"pH = (pK_a -logc)\/2 \\implies pK_a=2pH+logc"

"pK_a= 4.22-0.125=4.095=-logK_a"

"\\implies K_a=10^{-4.095}= 8.035*10^{-5}"

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