T = 15.00C = 288.15K
p = 1.10atm = 111.46 kPa
R = 8.31J/mol-K
pV = nRT
V = nRT/p = (0.600mol × 8.31J/mol-K × 288.15K) / 111.46kPa = 12.89L
Answer: 12.89L
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Dear madisan pree please post a new task
Calculate the approximate volume of a 0.62 mol sample of gas at 10.6 °C and a pressure of 1.05 atm.
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Dear madisan pree please post a new task
Calculate the approximate volume of a 0.62 mol sample of gas at 10.6 °C and a pressure of 1.05 atm.
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