Question

A 25.0 mL sample of 0.150 M HIO3 is titrated with 0.240 M Sr(OH)2. What volume of Sr(OH)2 is required to reach the equivalence point?

Answer 1

$2HIO_3+Sr(OH)_2\to Sr(IO_3)_2+2H_2O$

Let $M_1=0.15M,V_1=25\ ml,n_1=2;$

$M_2=0.24 M,n_2=1,V_2=?$

By Molarity equation,

$\frac{M_1V_1}{n_1}=\frac{M_2V_2}{n_2}\implies$

$\frac{0.15\times 25}{2}=\frac{0.24\times V_2}{1}$ $\implies V_2=7.81 \ ml$