Answer to Question #118158 in General Chemistry for Amanda

Question

What mass of HCl(g) is required to dissolve in 1.50 L of water to make an acidic solution with a
pH of 1.53

Answer 1

[H+]=antilog(1.5)= 0.0295120922667.

Cm=n/V.

n=Cm x V =0.0295120922667 x 1.5 = 0,0442681384 moles of HCl.

m=0,0442681384 x 36.5 = 1,61578705 g of HCl.