using formula or depression in freezing point
∆Tf = -Kf*m
Kf is given 1.99 °C/m
molality is 0.40 molal
so ∆Tf=- 1.99*0.40
∆Tf = -0.796°C
T2-T1=-0.796°C
T1 is given -114.1°C
so T2=-118.96°C
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