Question

Calculate the keq for CO (g) + 3H₂(g) ⇄ CH₄ (g) + H₂O (g) using the data [CO] = .0613 mol/L, [H₂] = .1839 mol/L, [CH₄] = .0387 mol/L, and [H₂O] = .0387 mol/L.

Answer 1

$CO (g) + 3H₂(g) ⇄ CH₄ (g) + H₂O (g)$

For the above reaction

K_eq=$\dfrac{[CH_4][H_2O]}{[H_2]^3[CO]}=\dfrac{0.387\times0.387}{0.0613\times(0.1839)^3}=392.84$