Question #118149
The Saturn V was the most powerful rocket ever built and was central to the success of the Apollo program in the 1960s. The rocket used liquid oxygen (O2) as a component of its propellant systems in all three stages.
Consider a liquid oxygen (O2) tank within the rocket of volume 443968 L. How many molecules of O2 would be present in this tank? The density of liquid oxygen is 1.14 kg/L.

Express your answer to two significant figures.
1
Expert's answer
2020-05-25T14:12:56-0400

Applying formula

density=massvolumedensity=\frac{mass}{volume }

mass=1.14×443968=506123.52kgmass =1.14\times443968=506123.52 kg=506123520grams=506123520grams


Let's calculate the moles of oxygen

no. of moles=given massmolar mass=50612352032=15816360=1.58×107moles=\frac{given\ mass }{molar\ mass }=\frac{506123520}{32}=15816360=1.58\times10^7 moles


1 mole contains 6.023×10236.023\times10^{23} molecules

1.58×1071.58\times10^7 mole will contain 1.58×107×6.023×1023molecules=9.51×10301.58\times10^7\times6.023\times10^{23} molecules =9.51\times10^{30} molecules


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