Question

What final solution volume would be required to prepare a 0.100 mol/L solution of
AgNO 3(aq) if 1.20 g of the solid salt will be used?

Answer 1

molarity=$\frac{moles}{volume \ in \ litres }$

Let's calculate the moles of silver nitrate first = $\frac{1.2}{170}=7\times10^{-3} moles$

now substituting the value in the above equation

$0.1=\frac{7\times10^{-3}}{V}$

$V=70\times10^{-3}litres$

$V=70 ml$