Question

If 120.0 g of CH4 is mixed with 120.0 g of H2O, how many grams of H2 is produced?

Answer 1

$CH_4+H_2O\to CO+3H_2$

As per the above equation,

$1$ mole of methane reacts with $1$ mole of water to produce $3$ moles of Hydrogen.

Moles of methane in $120\ g=\frac{120}{16}=7.5$

Moles of water in $120\ g=\frac{120}{18}=6.66$

So, water is a limiting reagent and hydrogen formation will depend on mass of water reacted.

Moles of hydrogen reacted$=3\times \frac{120}{18}=20$

Mass of $H_2$ produced$=2\times 20= 40 \ g$