Question

Calculate the percentage of K2O content of the base containing 65% potassium hydroxide

Answer 1

Suppose there is 100 g of base, in which 0.65*100 = 65 g KOH is contained.

It corresponds to 65 g / 56.1 g/mole = 1.158 mole of KOH, so that the number of moles of K2O is 1.158/2 = 0.579 mole of K2O.

Mass of K2O is 0.579 mole * 94.2 g/mole = 54.57 g.

Dividing by 100 g of the base, the percentage of K2O is 54.57 %.