Answer to Question #113929 in General Chemistry for Jonathan

Question

5.) A 14 ml solution of KOH has a concentration of 0.315 M. Calculate the pH and then calculate the amount of KOH in grams in solution.

Answer 1

KOH = K⁺ + OH^-

[OH^-] = 0.315 M

pOH = - log[OH^-]

pOH = 0.502

pH = 14 - 0.502 = 13.5

(14 / 1000) L * 0.315 M = 0.00441 mol

M (KOH) = 56.11 g/mol

m = 56.11 * 0.00441 = 0.247 g