Solution.
C=mM×V=ρMC = \frac{m}{M \times V} = \frac{\rho}{M}C=M×Vm=Mρ
M=ρ(VVm)=458.18 g/molM = \frac{\rho}{(\frac{V}{Vm})} = 458.18 \ g/molM=(VmV)ρ=458.18 g/mol
C=0.0011 MC = 0.0011 \ MC=0.0011 M
pH=−lg[H+]=2.96pH = -lg[H^+] = 2.96pH=−lg[H+]=2.96
Answer:
M = 458.18 g/mol
C = 0.0011 M
pH = 2.96
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