Answer to Question #113312 in General Chemistry for tasanee

Question

Nitrogen dioxide reacts with water to produce oxygen and ammonia:
4NO2(g)+6H2O(g)→7O2(g)+4NH3(g). How many grams of NH3 can be produced when 4.50 L of NO2 reacts at 435 ∘C and 695 mmHg ?

Answer 1

pV=nRT. n=pV/RT = 695 x 4500 / 62400 x 708= 0,0707912321 moles.

0,0707912321 x 17 = 1,20345095 g.