Solution.
∆G0=∆H0-T∆S0.
∆S0= -176,6 J/K= -0,1766 kJ/K.
∆G0298= -58,03-298*(-0,1766) =-5,4032 kJ.
Since ∆G0298< 0 the reaction is spontaneous.
Answer: ∆G0298 = -5,4032 kJ. The reaction is spontaneous.
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