The electrochemical reaction of silver is –
Ag+(aq) + e- = Ag(s)
The solution can be find out by following the Faraday’s first law of electrolysis.
This law states that the mass of a substance liberated at the electrode is directly proportional to the quantity of electricity passed through the electrolyte.
m = E x Q
m - mass of substance deposited or liberated;
E - electrochemical equivalent;
Q - quantity of current.
m = M x (I x t / Z x F) = 108 g/mol x (1.4 C/s x 3600 s / 1 x 96500 C/mol) = 5.641 g
Comments
Leave a comment