m=17.2 g
M(C2H6)=30.07 g/mol
V=6.54 L
P=715 mm Hg = 0.9408 atm
n=m/M
n=(17.2 g)/(30.07 g/mol)=0.572 mol
Ideal gas law:
PV=nRT
Molar gas constant
R=0.082058 L×atm/(K×mol)
(0.9408 atm)×(6.54 L)=(0.572 mol)×(0.082058 L×atm/(K×mol))×T
T=((0.9408 atm)×(6.54 L))/((0.572 mol)×(0.082058 L×atm/(K×mol)))
T= 131 K
Answer: 131 K
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