Question #113103
What is the pOH of a 0.0031M solution of the strong acid HBr?
1
Expert's answer
2020-05-01T14:41:11-0400

HBr →\to H+ + Cl-

pH = - log[H+] = -log(0.0031)= 2.51

pH + pOH = 14

pOH=14 - pH = 14-2.51= 11.49


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