Question #112981
Calculate the standard entropy change for the reaction at 25 °C. Standard molar entropy values can be found in this table.

H2O(g)+C(graphite)(s)⟶H2(g)+CO(g)
1
Expert's answer
2020-05-01T14:41:40-0400

Here we can find the standard value of entropy from the table in which it is given that


ΔSf(C)=5.59,ΔSf(H2O)=188.72,ΔSf(CO)=197.9,ΔSf(H2)=130.59\Delta S_f(C)=5.59,\Delta S_f(H_2O)=188.72,\Delta S_f(CO)=197.9 ,\Delta S_f(H_2)=130.59


Entropy change for the reaction can be calculated as follows


ΔSrxn=(ΔSf(CO)+ΔSf(H2))(ΔSf(C)+ΔSf(H2O))\Delta S_{rxn}= (\Delta S_f(CO) + \Delta S_f(H_2))-(\Delta S_f(C) + \Delta S_f(H_2O))


ΔSrxn=(197.9+130.59)(5.59+188.72)\Delta S_{rxn}=(197.9+130.59)-(5.59+188.72)


ΔSrxn=134.08\Delta S_{rxn}=134.08 J/K



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