Here we can find the standard value of entropy from the table in which it is given that
ΔSf(C)=5.59,ΔSf(H2O)=188.72,ΔSf(CO)=197.9,ΔSf(H2)=130.59
Entropy change for the reaction can be calculated as follows
ΔSrxn=(ΔSf(CO)+ΔSf(H2))−(ΔSf(C)+ΔSf(H2O))
ΔSrxn=(197.9+130.59)−(5.59+188.72)
ΔSrxn=134.08 J/K
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